1.00 mL of a 0.0500 M sucrose solution is transferred to a 100 mL volumetric flask, and the flask brought up to volume. 5.00 mL are taken from the 100 mL volumetric flask and transferred to a 0.500 L flask, and it is brought up to volume. What is the resulting concentration of sucrose in the 0.500 L flask?

You have 1 x 0.0500 = 0.0500 mmoles or 5E-5 moles in the 100 mL flask. That is then diluted so the new concn is

5E-5M x (5.00 mL/500 mL) = 5E-7M

where did u get 500ml?

To find the resulting concentration of sucrose in the 0.500 L flask, we need to use the concept of dilution.

First, let's calculate the amount of sucrose in the initial 1.00 mL sample. We can do this by multiplying the volume (1.00 mL) by the concentration of sucrose (0.0500 M). This gives us:

Amount of sucrose = (1.00 mL) x (0.0500 M) = 0.0500 millimoles (mmol) of sucrose

Next, let's consider the 100 mL volumetric flask. When the 1.00 mL sample is transferred to this flask and brought up to volume, the total amount of sucrose remains the same. Thus, we still have 0.0500 mmol of sucrose in the 100 mL flask.

Now, we'll calculate the concentration of sucrose in the 100 mL flask. We can use the formula:

Concentration (C1) x Volume (V1) = Concentration (C2) x Volume (V2)

Where:
C1 = initial concentration of sucrose (0.0500 M)
V1 = initial volume of sucrose (0.00100 L)
C2 = final concentration of sucrose (what we're trying to find)
V2 = final volume of sucrose (0.100 L)

Rearranging the formula, we have:

C2 = (C1 x V1) / V2
C2 = (0.0500 M) x (0.00100 L) / (0.100 L)
C2 = 0.0005 M = 0.500 mM (millimolar)

So, the concentration of sucrose in the 100 mL flask is 0.500 mM.

Finally, let's consider the 0.500 L flask. When 5.00 mL of the solution from the 100 mL flask is transferred into it and brought up to volume, the total amount of sucrose remains the same. Therefore, we still have 0.0500 mmol of sucrose in the 0.500 L flask.

To find the concentration of sucrose in the 0.500 L flask, we can apply the same formula as before:

C1 x V1 = C2 x V2

Where:
C1 = initial concentration of sucrose (0.500 mM)
V1 = initial volume of sucrose (0.00500 L)
C2 = final concentration of sucrose (what we're trying to find)
V2 = final volume of sucrose (0.500 L)

Rearranging the formula, we have:

C2 = (C1 x V1) / V2
C2 = (0.500 mM) x (0.00500 L) / (0.500 L)
C2 = 0.005 mM = 0.005 M

Therefore, the resulting concentration of sucrose in the 0.500 L flask is 0.005 M.