Posted by Eun on Sunday, October 9, 2011 at 11:06pm.
Let the distance from home to the runner be d.
Let the distance from first base to the runner be x
d^2 = 90^2 + x^2
2d dd = 2x dx
when x = 45, d = 45 sqrt(5) = 100.62
201.24 dd = 90 (20)
dd = 1800/201.24 = 8.94 ft/s
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can't read 2nd problem - font garbling
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h/25 = tan(theta)
dh/25 = sec^2(theta) * dtheta
-5/25 = 2 * dtheta
-.1 = dtheta
For 2, I got 0.625 in/sec. dA/dt is pi/2.
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