Sample of 10.7 g of CO reacts completely with O2 to form CO2. How many grams of CO2 will be formed?
To find out how many grams of CO2 will be formed when 10.7 g of CO reacts completely with O2, we need to use stoichiometry. Stoichiometry is a calculation method that uses the balanced chemical equation to determine the relationship between the reactants and products in a chemical reaction.
The balanced chemical equation for the reaction between CO and O2 to form CO2 is:
2 CO + O2 -> 2 CO2
From the balanced equation, we can see that 2 moles of CO react with 1 mole of O2 to produce 2 moles of CO2.
To calculate the amount of CO2 formed, we can follow these steps:
Step 1: Convert the given mass of CO to moles.
To do this, we need to know the molar mass of CO, which is 28.01 g/mol (12.01 g/mol for carbon + 16.00 g/mol for oxygen).
Using the formula: moles = mass / molar mass, we can calculate the moles of CO:
moles of CO = 10.7 g / 28.01 g/mol
Step 2: Using the mole ratio from the balanced equation, determine the moles of CO2 formed.
From the balanced equation, we know that 2 moles of CO react to form 2 moles of CO2.
So, the moles of CO2 formed will be equal to the moles of CO. In this case, it will be equal to the result obtained in step 1.
Step 3: Convert the moles of CO2 to grams.
To do this, we need to know the molar mass of CO2, which is 44.01 g/mol (12.01 g/mol for carbon + 2 * 16.00 g/mol for oxygen).
Using the formula: mass = moles * molar mass, we can calculate the mass of CO2:
mass of CO2 = moles of CO2 * 44.01 g/mol
Let's calculate the result:
Step 1: moles of CO = 10.7 g / 28.01 g/mol = 0.382 mol
Step 2: The moles of CO2 formed will be equal to the moles of CO, which is 0.382 mol.
Step 3: mass of CO2 = 0.382 mol * 44.01 g/mol = 16.82 g
Therefore, when 10.7 g of CO reacts completely with O2, it will produce 16.82 grams of CO2.
This is a stoichiometry problem. Here is a worked example. Just follow the steps.
http://www.jiskha.com/science/chemistry/stoichiometry.html