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March 26, 2017

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How many mL of 0.139 M KOH are needed to reach the equivalence point when 1.8 g of potassium hydrogen phthalate, KHP is titrated to a phenolphthalein end-point.

  • Chemistry - ,

    Write the equation and balance it.
    Convert 1.8 g KHP to moles. moles = grams/molar mass
    Convert moles KHP to moles NaOH using the coefficients in the balanced equation.
    Finally, M NaOH = moles NaOH/L NaOH. Solve for L NaOH and convert to mL.

  • Chemistry--Typo - ,

    That's KOH and not NaOH.

  • Chemistry - ,

    1.22

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