Post a New Question


posted by on .

How many mL of 0.139 M KOH are needed to reach the equivalence point when 1.8 g of potassium hydrogen phthalate, KHP is titrated to a phenolphthalein end-point.

  • Chemistry - ,

    Write the equation and balance it.
    Convert 1.8 g KHP to moles. moles = grams/molar mass
    Convert moles KHP to moles NaOH using the coefficients in the balanced equation.
    Finally, M NaOH = moles NaOH/L NaOH. Solve for L NaOH and convert to mL.

  • Chemistry--Typo - ,

    That's KOH and not NaOH.

  • Chemistry - ,


Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question