Homework Help: Chemistry

Posted by Anonymous on Sunday, October 9, 2011 at 10:24pm.

How many mL of 0.139 M KOH are needed to reach the equivalence point when 1.8 g of potassium hydrogen phthalate, KHP is titrated to a phenolphthalein end-point.

Chemistry - DrBob222, Monday, October 10, 2011 at 12:05am
Write the equation and balance it.
Convert 1.8 g KHP to moles. moles = grams/molar mass
Convert moles KHP to moles NaOH using the coefficients in the balanced equation.
Finally, M NaOH = moles NaOH/L NaOH. Solve for L NaOH and convert to mL.
Chemistry--Typo - DrBob222, Monday, October 10, 2011 at 12:06am
That's KOH and not NaOH.
Chemistry - Anonymous, Monday, December 12, 2011 at 9:44am
1.22

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