Thursday

April 24, 2014

April 24, 2014

Posted by **Anne** on Sunday, October 9, 2011 at 9:04pm.

Show all work

- Algebra -
**Reiny**, Sunday, October 9, 2011 at 9:14pmrate = job/time

let the time of the faster pump be t min

let the time of slower pump be 3t min

rate of slower = job/(3t)

rate of faster = job/t

combined rate = job/(3t) + job/t

= (job + 3job)/(3t) = 4job/(3t)

time working together = job/(4job/3t)) = 45

job(3t)/(4job) = 45

3t/4= 45

t = 60

Using only the first pump would require 60 minutes.

**Related Questions**

algebra - Two pumps can fill a water tank in 256 minutes when working together. ...

science - a large fiberglass tank was placed in a pit, before pipes could be ...

Math - Tap A fills up a water tank in 45 mins. Tap A fills up_____(ugh soo right...

college algebra - water from a tank is being used for irrigation while the tank ...

algebra - Joe's larger tank is completely filled with water. He takes water from...

math - 3 pumps, working 6 hours a day, can empy a water tank in 2 days. How many...

college algebra - A paint-mixing machine has 2 inlet pipes. One takes 1 hour ...

algebra - Joe's larger tank is completely filled with water. He takes water from...

algebra - Joe's larger tank is completely filled with water. He takes water from...

physics - A fire hose can fill a certain tank with water during 1 hour. A 2nd ...