Saturday

October 25, 2014

October 25, 2014

Posted by **Anne** on Sunday, October 9, 2011 at 9:04pm.

Show all work

- Algebra -
**Reiny**, Sunday, October 9, 2011 at 9:14pmrate = job/time

let the time of the faster pump be t min

let the time of slower pump be 3t min

rate of slower = job/(3t)

rate of faster = job/t

combined rate = job/(3t) + job/t

= (job + 3job)/(3t) = 4job/(3t)

time working together = job/(4job/3t)) = 45

job(3t)/(4job) = 45

3t/4= 45

t = 60

Using only the first pump would require 60 minutes.

**Answer this Question**

**Related Questions**

algebra - Two pumps can fill a water tank in 256 minutes when working together. ...

maths - One pump fills a tank two times as fast as another pump. If the pumps ...

Algebra I - Pump A, working alone, can fill a tank in 3 hours, and pump B can ...

math - Filling a tank. Two pipes are connected to the same tank. Working ...

Math - The Timuga swimming pool, of Manila City has two pumps it uses to fill ...

college algebra - A paint-mixing machine has 2 inlet pipes. One takes 1 hour ...

akgebra - One pipe can fill a tank in 20 minutes, while another takes 30 minutes...

Math - Two faucets can fill a tank in 1 hour and 20 minutes. The first faucet ...

algebra - Pump A can fill a swimming pool in 6 hours and pump B can fill the ...

science - a large fiberglass tank was placed in a pit, before pipes could be ...