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September 21, 2014

September 21, 2014

Posted by **Anne** on Sunday, October 9, 2011 at 9:04pm.

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- Algebra -
**Reiny**, Sunday, October 9, 2011 at 9:14pmrate = job/time

let the time of the faster pump be t min

let the time of slower pump be 3t min

rate of slower = job/(3t)

rate of faster = job/t

combined rate = job/(3t) + job/t

= (job + 3job)/(3t) = 4job/(3t)

time working together = job/(4job/3t)) = 45

job(3t)/(4job) = 45

3t/4= 45

t = 60

Using only the first pump would require 60 minutes.

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