Posted by **John** on Sunday, October 9, 2011 at 6:57pm.

y sin 12x = x cos 2y, (pi/2, pi/4)

Find the tangent line to the curve at the given point.

y=???

- calculus -
**bobpursley**, Sunday, October 9, 2011 at 7:02pm
dy/dx * sin12x+ 12 y cos12x= cos2y-xsin2y dy/dx

dy/dx(sin12x+xsin2y)=cos2y-12ycos12x

first, solve for dy/dx, that is the slope.at x,y.

y= mx+b

Now put in the x,y in that equation, and solve for b.

- calculus -
**John**, Sunday, October 9, 2011 at 7:23pm
Can anyone else elaborate?

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