Posted by Paul on Sunday, October 9, 2011 at 5:30pm.
I haven't done the calcs, but how can you just have a magnitude? This is a vector addition of two components of E.
yes, I added the vectors, of the charges. for a uniform line, E= kλ/R. Since the charge on the line is negative, it goes towards the line, and only has an x component of E= -12 kN/C. For the point charge, which is negative, E is away from the source, I got E=30.2 kN/C for the x component, and -15.1 kN/c for the y component. I added the x components, and then found the final magnitude with sqrt(x^2+y^2) as 23.7kN/C. But that is the wrong answer.
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