Write balanced molecular and net ionic equations for the reaction of KHP with NaOH.

To write a balanced molecular and net ionic equation for the reaction of KHP (potassium hydrogen phthalate) with NaOH (sodium hydroxide), we need to identify the reactants and products involved.

Reactants:
1. KHP (potassium hydrogen phthalate): KHC8H4O4
2. NaOH (sodium hydroxide): NaOH

Products:
1. Water (H2O)
2. Potassium hydroxide (KOH)
3. Phthalic acid (C8H6O4)

Step 1: Balanced Molecular Equation
The molecular equation represents the overall reaction, showing all the reactants and products without indicating their charges or states.

KHP + NaOH → H2O + KOH + C8H6O4

Step 2: Ionic Equation
The ionic equation shows the dissociation of soluble ionic compounds into their respective ions.

KHP + NaOH → H2O + KOH + C8H6O4

Since KHP and C8H6O4 are not ionic compounds, they do not dissociate into ions.

Step 3: Net Ionic Equation
The net ionic equation only includes the species that are directly involved in the reaction. It eliminates spectator ions that do not participate in the chemical change.

In this case, the only species that undergo a chemical change are H+ from KHP and OH- from NaOH, which combine to form water.

H+ (aq) + OH- (aq) → H2O (l)

Thus, the net ionic equation for the reaction of KHP with NaOH is:

H+ (aq) + OH- (aq) → H2O (l)

The balanced molecular equation for the reaction of Potassium Hydrogen Phthalate (KHP) with Sodium Hydroxide (NaOH) is:

KHP (C8H5O4K) + NaOH → H2O + NaKC8H4O4

To write the net ionic equation, we need to identify the spectator ions, which are the ions that do not participate in the chemical reaction. In this case, the spectator ions are K+ (Potassium) and Na+ (Sodium).

The net ionic equation for the reaction of KHP with NaOH is:

H+ + OH- → H2O

This equation represents the actual chemical reaction that occurs, with the spectator ions removed.