four times the difference or two posotive integer numbers is equal to half the sum of the numbers. If one of the numbers is 14, what is the other number?

I just cant get this can anyone help me?

let x = the other number

then we set-up the equation.
4*(x-14) = (1/2)*(x+14)
4x - 56 = (1/2)x + 7
4x - 0.5x = 56 + 7
3.5x = 63
x = 18

hope this helps~ :)

Sure, I can help you with that.

Let's break down the problem step by step:

We are given that "four times the difference of two positive integer numbers is equal to half the sum of the numbers".

Let's assume the two numbers are x and 14 (as one of the numbers is given as 14).

According to the problem statement, we can write the equation as:

4(x - 14) = (x + 14) / 2

Now, let's solve this equation step by step:

1. Distribute the 4 on the left side of the equation:
4x - 4 * 14 = (x + 14) / 2

2. Simplify:
4x - 56 = (x + 14) / 2

3. Multiply both sides of the equation by 2 to eliminate the fraction:
2 * (4x - 56) = 2 * ((x + 14) / 2)
8x - 112 = x + 14

4. Simplify:
8x - x = 14 + 112
7x = 126

5. Divide both sides of the equation by 7 to isolate x:
x = 126 / 7
x = 18

So, the other number is 18.

To summarize, we assumed the two numbers as x and 14, and then set up the equation according to the problem statement. We solved the equation step by step to find that the other number is 18.