sodium sulfide, Na2S, is used in the leather industry to remove hair from hides. The Na2SO4 + 4C -> Na2S +4CO(g) so suppose you mix 15(g) of Na2SO4 and 7.5g of C. which is the limiting reactant AND what is mass of Na2S that is produced?

two reactants are copper(II)chloride and water what change would you observe in the copper(II)oxide. was there a change in solubility? where is the copper(II) chloride? how can you tell

I think the limiting agent is sodium sulfate...

and the mass of sodium sulfide is 8.268 grams

To determine the limiting reactant and the mass of Na2S produced, we need to compare the moles of Na2SO4 and C.

1. Calculate the moles of Na2SO4:
The molar mass of Na2SO4 is 142.04 g/mol.
Moles of Na2SO4 = Mass of Na2SO4 / Molar mass of Na2SO4
= 15 g / 142.04 g/mol

2. Calculate the moles of C:
The molar mass of C is 12.01 g/mol.
Moles of C = Mass of C / Molar mass of C
= 7.5 g / 12.01 g/mol

3. Use the balanced equation to determine the stoichiometric ratio between Na2SO4 and C:
From the equation Na2SO4 + 4C -> Na2S + 4CO(g), the stoichiometric ratio between Na2SO4 and C is 1:4.

4. Compare moles to find the limiting reactant:
Since the stoichiometric ratio is 1:4, we need to compare the moles of Na2SO4 and C.
If the moles of Na2SO4 is greater, then Na2SO4 is the limiting reactant, and vice versa.

5. Calculate the moles of Na2S produced:
Since the stoichiometric ratio between Na2SO4 and Na2S is also 1:1, the number of moles of Na2S produced is equal to the number of moles of the limiting reactant.

6. Calculate the mass of Na2S produced:
Mass of Na2S = Moles of Na2S * Molar mass of Na2S

By following these steps, you can determine the limiting reactant and the mass of Na2S produced in the given reaction.