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August 1, 2014

August 1, 2014

Posted by **vicki** on Sunday, October 9, 2011 at 12:11pm.

- calculus -
**Steve**, Sunday, October 9, 2011 at 6:35pmIf you mean (x^2+1) * (x^2+2)^(1/3) then just use the product rule and chain rule.

y = u*v^n

y' = u'v^n + u*n*v^(n-1)*v'

u = x^2 + 1

u' = 2x

v = x^2 + 2

v' = 2x

y' = 2x*cbrt(x^2+2) + 2x*(x^2+1)* 1/3 * (x^2 + 2)^(-2/3)

Feel free to simplify further. You're doing calculus; algebra should be a breeze.

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