Thursday

December 18, 2014

December 18, 2014

Posted by **Prater** on Saturday, October 8, 2011 at 10:56pm.

vave = y(t2) − y(t1)/t2 − t1.

We are given that

y = 14t − 1.86t^2.

Evaluating at

t = 1,

we have

y(1) = 14(1) − 1.86(1)2 = 12.14.

Thus, the average velocity between times 1 and 1 + h is as follows.

vave = y(1 + h) − y(1)/(1 + h) − 1

= [14(1 + h) − 1.86(1 + h)^2] − 12.14/h

=10.28h − _____h^2/h

= ____ − _______h, h ≠ 0

- Calculus -
**Steve**, Sunday, October 9, 2011 at 3:01pm(10.28h - 3,46h^2)/h

10.28 - 3.46h

Man, how could you get that far, and be stumped by 1.86^2?

**Answer this Question**

**Related Questions**

Calc - Recall that the average velocity between times t1and t2 is calculated ...

biology - Given the part of the molecule shown below, can the underlined atom ...

Grade 12 Calculus - Evaluate each of the following. Show all your calculations...

calculus (gr 12) - Evaluate each of the following. Show all your calculations. a...

calculus (gr 12) - Evaluate each of the following. Show all your calculations. a...

calculus - Find an equation for the surface consisting of all points P(x, y, z) ...

Calculus - If a rock is thrown upward on the planet Mars with a velocity of 14 m...

Chemistry - In the redox conversion of CO to CO2− 3 , the oxidation number...

physics - Four charges −8 × 10^−9 C at (0 m, 0 m), −7 × 10^&#...

chemistry - For which of these elements would the electron affinity process ...