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August 30, 2014

August 30, 2014

Posted by **Prater** on Saturday, October 8, 2011 at 10:56pm.

vave = y(t2) − y(t1)/t2 − t1.

We are given that

y = 14t − 1.86t^2.

Evaluating at

t = 1,

we have

y(1) = 14(1) − 1.86(1)2 = 12.14.

Thus, the average velocity between times 1 and 1 + h is as follows.

vave = y(1 + h) − y(1)/(1 + h) − 1

= [14(1 + h) − 1.86(1 + h)^2] − 12.14/h

=10.28h − _____h^2/h

= ____ − _______h, h ≠ 0

- Calculus -
**Steve**, Sunday, October 9, 2011 at 3:01pm(10.28h - 3,46h^2)/h

10.28 - 3.46h

Man, how could you get that far, and be stumped by 1.86^2?

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