Posted by **Prater** on Saturday, October 8, 2011 at 10:56pm.

Recall that the average velocity between times t1and t2 is calculated using

vave = y(t2) − y(t1)/t2 − t1.

We are given that

y = 14t − 1.86t^2.

Evaluating at

t = 1,

we have

y(1) = 14(1) − 1.86(1)2 = 12.14.

Thus, the average velocity between times 1 and 1 + h is as follows.

vave = y(1 + h) − y(1)/(1 + h) − 1

= [14(1 + h) − 1.86(1 + h)^2] − 12.14/h

=10.28h − _____h^2/h

= ____ − _______h, h ≠ 0

## Answer this Question

## Related Questions

- Calc - Recall that the average velocity between times t1and t2 is calculated ...
- biology - Given the part of the molecule shown below, can the underlined atom ...
- Grade 12 Calculus - Evaluate each of the following. Show all your calculations...
- calculus (gr 12) - Evaluate each of the following. Show all your calculations. a...
- calculus (gr 12) - Evaluate each of the following. Show all your calculations. a...
- calculus - Find an equation for the surface consisting of all points P(x, y, z) ...
- Calculus - If a rock is thrown upward on the planet Mars with a velocity of 14 m...
- calculus - When a ball is thrown vertically upward into the air with a velocity ...
- Chemistry - In the redox conversion of CO to CO2− 3 , the oxidation number...
- physics - Four charges −8 × 10^−9 C at (0 m, 0 m), −7 × 10^&#...

More Related Questions