posted by anonymous .
A 0.45kg shuffleboard puck is given an initial velocity down the playing surface of 4.5 m/s. If the coefficient of friction between the puck and the surface is 0.20, how far will the puck slide before coming to rest?
It will slide a distance X until the work done against friction equals the initial kinetic energy.
M*g*mu*X = (1/2) M V^2
X = V^2/(2*g*mu)
mu is the coefficient of kinetic friction, 0.20 in this case.