Calculate the amount (in moles) of H₂O in 2.00g of Na₂CO₃ ⋅ 10H₂O.
Thanks so much!!
moles Na2CO3.10H2O = grams/molar mass = ?
? Moles Na2CO3.10H2O x (10 moles H2O/1 mole Na2CO2.10H2O) = ?mols H2O in 2 g of the decahydrate.
To calculate the amount of H₂O in 2.00g of Na₂CO₃ ⋅ 10H₂O in moles, we need to follow these steps:
1. Determine the molar mass of Na₂CO₃ ⋅ 10H₂O.
- The molar mass of Na is 22.99 g/mol.
- The molar mass of C is 12.01 g/mol.
- The molar mass of O is 16.00 g/mol.
- The molar mass of H is 1.01 g/mol.
- Since there are two Na atoms, one C atom, and three O atoms in Na₂CO₃, we can calculate the molar mass as follows:
Molar mass of Na₂CO₃ = (2 * 22.99 g/mol) + (1 * 12.01 g/mol) + (3 * 16.00 g/mol) = 105.99 g/mol.
2. Calculate the molar mass of water (H₂O).
- The molar mass of H₂O is (2 * 1.01 g/mol) + (1 * 16.00 g/mol) = 18.02 g/mol.
3. Calculate the number of moles of Na₂CO₃ ⋅ 10H₂O.
- Number of moles = Mass of the compound / Molar mass
- Number of moles of Na₂CO₃ ⋅ 10H₂O = 2.00g / 105.99 g/mol
4. Determine the number of moles of H₂O.
- Since Na₂CO₃ ⋅ 10H₂O contains 10 water molecules, the number of moles of H₂O is:
Number of moles of H₂O = Number of moles of Na₂CO₃ ⋅ 10H₂O * 10
By following these steps, you can calculate the amount of H₂O in moles in 2.00g of Na₂CO₃ ⋅ 10H₂O.