posted by Allie .
A dentist's drill starts from rest. After 3.30 s of constant angular acceleration it turns at a rate of 2.1x10^4 rev/min.
(a) Find the drill's angular acceleration.
(b) Determine the angle (in radians) through which the drill rotates during this period.
(a) Divide the final angular velocity (in rad/s, NOT rpm) by the time interval.
(b) angle = (1/2)*(angular acceleration)*t^2
(1/2)*(final angular velocity)*time
Why do you multiply by .5?
it is based off the equation:
displacement = (initial velocity)*(change in time) + 1/2(acceleration)*(change in time squared)
since that equation is linear, the equation recommended for this problem is:
"angle" = 0 + 1/2(acceleration)*(change in time squared)
that is how one gets the 1/2