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A dentist's drill starts from rest. After 3.30 s of constant angular acceleration it turns at a rate of 2.1x10^4 rev/min.
(a) Find the drill's angular acceleration.

(b) Determine the angle (in radians) through which the drill rotates during this period.

  • Physics -

    (a) Divide the final angular velocity (in rad/s, NOT rpm) by the time interval.

    (b) angle = (1/2)*(angular acceleration)*t^2
    (1/2)*(final angular velocity)*time

  • Physics -

    Why do you multiply by .5?

  • Physics -

    it is based off the equation:

    displacement = (initial velocity)*(change in time) + 1/2(acceleration)*(change in time squared)

    since that equation is linear, the equation recommended for this problem is:

    "angle" = 0 + 1/2(acceleration)*(change in time squared)

    that is how one gets the 1/2

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