Posted by **Hope ** on Friday, October 7, 2011 at 12:00pm.

I have provided information from #3-5 in order to answer #6..

3. Give the mean for the mean column of the Worksheet. Is this estimate centered about the parameter of interest (the parameter of interest is the answer for the mean in question 2)?

The Mean for Column “mean” is 3.56 It is very close to the parameter of interest but is not equal to it. You could calculate a confidence interval for the mean of the mean column, but a specific confidence interval would need to be provided. In that case, the confidence interval would be centered on 3.56, not 3.5.

4. Give the mean for the median column of the Worksheet. Is this estimate centered about the parameter of interest (the parameter of interest is the answer for the mean in question 2)?

The Mean for the Median column is 3.6 The mean here is close to the mean in question 2, but is not as close as the answer from question 3.

.

5. Give the standard deviation for the mean and median column. Compare these and be sure to identify which has the least variability?

Standard deviation of Mean = 0.4762

Standard deviation of Median = 0.7539

The Standard Deviation of the Mean being smaller, all the data points will tend to be very near the Mean. The Median with a larger Standard Deviation will tend to have data points spread out over a large range of values.

Since the Mean has the smaller of the Standard Deviations, it has the least variability

6. Based on questions 3, 4, and 5 is the mean or median a better estimate for the parameter of interest? Explain your reasoning.

- Statistics -
**Anonymous**, Tuesday, April 15, 2014 at 12:10am
mean

- Statistics -
**adriana**, Friday, June 26, 2015 at 12:03am
IDk

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