Posted by David on Friday, October 7, 2011 at 12:27am.
Find the points at which the following function is discontinuous.Indicate the intervals at which the function is continuous.
f(x)= (x^2 if x<1), (x if 1<x<=1), (3x+1 if 1<x)

calculus  Reiny, Friday, October 7, 2011 at 7:46am
looks like x = 1 is NOT included in any of the functions.

calculus  Steve, Friday, October 7, 2011 at 1:33pm
f is also discontinuous at x=1, since f(1) = 1, but f(1+h) = 4+h, which does not equal 1, no matter how small h is.

calculus  Steve, Friday, October 7, 2011 at 1:34pm
make that f(1+h) = 4 + 3h, but it's still nowhere near 1.
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