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March 31, 2015

March 31, 2015

Posted by **David** on Friday, October 7, 2011 at 12:27am.

f(x)= (x^2 if x<-1), (|x| if -1<x<=1), (3x+1 if 1<x)

- calculus -
**Reiny**, Friday, October 7, 2011 at 7:46amlooks like x = -1 is NOT included in any of the functions.

- calculus -
**Steve**, Friday, October 7, 2011 at 1:33pmf is also discontinuous at x=1, since f(1) = 1, but f(1+h) = 4+h, which does not equal 1, no matter how small h is.

- calculus -
**Steve**, Friday, October 7, 2011 at 1:34pmmake that f(1+h) = 4 + 3h, but it's still nowhere near 1.

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