Homework Help: big lake

Posted by sara on Thursday, October 6, 2011 at 10:12pm.

Two cyclists, 36 miles apart, start riding toward each other at the same time. One cycles 2 times as fast as the other. If they meet 2 hours later, what is the speed (in mi/h) of the faster cyclist?

big lake - Steve, Friday, October 7, 2011 at 6:04am
Both riders ride for 2 hours

add up their distances to be 36

distance = speed*time

2s + 2*2s = 36
6s=36
s=6

slow rider rides 2hrs*6mph = 12 mi
fast rider rides 2hrs*12mph = 24mi

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