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big lake

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Two cyclists, 36 miles apart, start riding toward each other at the same time. One cycles 2 times as fast as the other. If they meet 2 hours later, what is the speed (in mi/h) of the faster cyclist?

  • big lake - ,

    Both riders ride for 2 hours

    add up their distances to be 36

    distance = speed*time

    2s + 2*2s = 36
    6s=36
    s=6

    slow rider rides 2hrs*6mph = 12 mi
    fast rider rides 2hrs*12mph = 24mi

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