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August 2, 2014

August 2, 2014

Posted by **Sarah** on Thursday, October 6, 2011 at 8:22pm.

- MATH -
**Steve**, Friday, October 7, 2011 at 5:55amIf you draw two intersecting circles, E and P, then the intersection is for students in both E and P.

E = .3S

The intersection of P&E = .4E = .6P

But, that means that .12S = .6P, so P = .2S

Add up E & P to get .5S = 50%

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