Posted by Sarah on Thursday, October 6, 2011 at 8:22pm.
If you draw two intersecting circles, E and P, then the intersection is for students in both E and P.
E = .3S
The intersection of P&E = .4E = .6P
But, that means that .12S = .6P, so P = .2S
Add up E & P to get .5S = 50%
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