Sunday
March 26, 2017

Post a New Question

Posted by on .

Calculate [H3O] an [OH] for a sodium hydroxide solution having a pH of 12.5.

I'm having a hard time with this i'm not sure how to start it. Please help me!

  • chemistry 12 - ,

    I would start by converting pH to pOH.
    pH + pOH = pKw = 14
    Then solve for OH^= from
    pOH = -log(OH^-)

    Or you can go another way.
    pH = -log(H^+) and solve for (H^+), then
    (H^+)(OH^-) = Kw = 1E-14 and solve for OH^-

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question