Posted by randy on Thursday, October 6, 2011 at 6:28pm.
A ball is thrown upward at a speed v0 at an angle of 59.0¢ª above the horizontal. It reaches a maximum height of 8.7 m. How high would this ball go if it were thrown straight upward at speed v0?

physics  Henry, Friday, October 7, 2011 at 7:37pm
Yo = ver. = Vosin59 = 0.857Vo. = ver.
component of Vo.
Vf^2 = Yo^2 + 2g*d,
Yo^2 = Vf^2  2g*d,
Yo^2 = 0 + 19.6*8.7 = 170.52,
Yo = 13.06m/s.
Yo = 0.857Vo = 13.06m/s,
0.857Vo = 13.06,
Vo = 15.2m/s.
h = (Vf^2  Vo^2) / 2g,
h = (0  (15.2)^2) / 19.6 = 11.85m.
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