posted by Kasey on .
Suppose that 50 mL of 0.3 M LiOH and 60 mL of 0.1 M NaHSO3 are mixed.
What is the K for the dominant equilibrium in terms of Ka's, Kb's, Kw etc.?
Ka of HSO3-
1/Ka of HSO3-
Kb of OH-
1/Kb of OH-
Kb of SO3-2
1/Kb of SO3-2
There is no reaction.
LiOH + NaHSO3 ==> H2O + NaLiSO3
You have 50*0.3 = 15 mmoles LiOH
You have 50*0.1 = 5 mmoles NaHSO3
So you have 10 mmoles LiOH in excess (which is a strong base) with all of the NaHSO3 reacted. Thus the dominant equilibrium, as I see it, is the strong base of LiOH.