Homework Help: chemistry

Posted by Franky on Thursday, October 6, 2011 at 1:51pm.

Hi, the question is: in each reaction, identify what have been oxidised and reduced.

The equation is: 2Al + 3H2SO4 ---> Al2(SO4)3 + 3H2
I am confused about the Al2(SO4)3 I know what oxides and reductions us I just don't understant how Al2(SO4)3 balances out to O with the oxidation numbers. Please help!!!

chemistry - Steve, Thursday, October 6, 2011 at 2:19pm
Sulfuric acid exists in solution as H⁺ and HSO₄⁻ ions, but both react with Al metal to produce Al⁺ł ions and SO₄⁻˛ ions. The most accurate representation of what's going on is:
2Al(s) + 3H⁺ + 3HSO₄⁻ --> 3H₂(g) + 2Al⁺ł + 6SO₄⁻˛
or as ...
2Al(s) + 3H₂SO₄(aq) --> 3H₂(g) + Al₂(SO₄)₃(aq)
chemistry - Steve, Thursday, October 6, 2011 at 2:21pm
Make that 6SO₄⁻˛ a 3SO₄⁻˛
chemistry - Franky, Thursday, October 6, 2011 at 2:42pm
Thank you very much :)

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