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35%of adult Americans are regular voters. A random sample of 250 adults in a medium-size college town were surveyed, and it was found that 110 were regular voters. Estimate the true proportion of regular voters with 90% confidence and comment on your results...

Can you show you work please???

  • Statisics - ,

    Confidence interval using proportions:

    CI90 = p + or - (1.645)(√pq/n)
    ...where + or - 1.645 represents 90% confidence using a z-table.

    Note: p = 110/250 (convert to a decimal); q = 1 - p; and n = 250 (sample size).

    I'll let you take it from here.

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