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March 6, 2015

March 6, 2015

Posted by **Chole** on Wednesday, October 5, 2011 at 8:11pm.

- Math -
**Steve**, Thursday, October 6, 2011 at 12:13amlet p = area of photo = 59

let x be the width. So, the height is 59/x

m = (x+2)(59/x + 4)

m = 59 + 118/x + 4x + 8

to find max mounted area, set m' = 0

m' = -118/x² + 4 = (4x² - 118)/x^2

So, m' = 0 when 4x²-118 = 0

x² - 29.5 = 0

x = 5.43"

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