Wednesday

April 16, 2014

April 16, 2014

Posted by **Chole** on Wednesday, October 5, 2011 at 8:11pm.

- Math -
**Steve**, Thursday, October 6, 2011 at 12:13amlet p = area of photo = 59

let x be the width. So, the height is 59/x

m = (x+2)(59/x + 4)

m = 59 + 118/x + 4x + 8

to find max mounted area, set m' = 0

m' = -118/x² + 4 = (4x² - 118)/x^2

So, m' = 0 when 4x²-118 = 0

x² - 29.5 = 0

x = 5.43"

**Related Questions**

math - Rafael wants to 30 cenyimeters of wood to frame a rectangular photograph...

Math - Rafael wants to use 30 centimeters of wood to frame a rectangular photo. ...

Math algebra - the length of a rectangular photograph is 8in. more than the ...

math - A rectangular photograph is mounted on a rectangular card. There is a ...

math - A rectangular photograph is mounted on a rectangular card. There is a ...

maths - The width of a rectangular photograph is 5cm more than the height. The ...

maths - The width of a rectangular photograph is 5cm more than the height. The ...

Math - The area of a photograph is 15 square inches. If the width of the ...

math algebra - the length of a rectangular photograph is 11 in. more than the ...

algebra - the length of a rectangular photograph is 5in. more than the width. ...