Posted by Anonymous on .
a solution was perpared by dissolving 4.765 g of AlCl3 in enough water to give 250 mL of AlCl3?
a. how do you calculate the molarity of the solution
b. how do you calculate the osmolarity of the solution
determine the mole mass of aluminum chloride.
moles AlCl3= 4.765/molmass
Osmolarity= 4 times molarity