Posted by Sydney on Wednesday, October 5, 2011 at 7:55pm.
time in air:
vertical speed initial: 1.68E3 sin 37
hf=hi+Vi*t-1/2 g t^2
0=0+1.68E3 sin 37 *t-4.8t^2
solve for time of flight, t.
horizontal range:
distance= 1.68E3*cos37*t
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