physics
posted by Anonymous on .
When a 2.50kg object is hung vertically on a certain light spring described by Hooke's law, the spring stretches 3.13 cm.
a)What is the force constant of the spring?
b) If the 2.50kg object is removed, how far will the spring stretch if a 1.25kg block is hung on it?

k= force/x= mg/.0313
b) x= force/k=mg/k it better be half as far.