Posted by Alex L. on Wednesday, October 5, 2011 at 6:18pm.
This is not hard. Just start with 2, and divide it into the number as many times as you can. Then try 3,5,7,... for all primes up to sqrt(N). Why stop there? because if one factis greater than sqrt(N), the other factor will be less.
18
2*9
2*3*3 = 2*3^2
480
2*240
2*2*120
2*2*2*60
2*2*2*2*30
2^5 * 15
2^5 * 3 * 5
640
2^6 * 10
2^7 * 5
165/180
3*5*11/2*2*3*3*5
11/2*2*3
11/12
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