Posted by ahmed on Wednesday, October 5, 2011 at 5:06pm.
If it started at O (0,0), then after sailing NW, it arrives at P(-295 cos 35°, 295 sin 35°)
Now we want to arrive at point Q= (100,0)
SO, use the law of cosines to get the distance PQ: PQ² = 295² + 100² - 295*100*cos(180-35)
Now, use the law of sines to get the angle OPQ:
sin 145°/PQ = sin OPQ/100
Now, the heading is 55° + OPQ° east of south
Related Questions
physics - A ship leaves the island of Guam and sails a distance 295 at an angle ...
physics - A ship leaves the island of Guam and sails a distance 280 at an angle...
physics- i need help ASAP - A ship leaves the island of Guam and sails a ...
Trig - A ship leaves its homeport and sails on a bearing of N28degrees10'E. ...
I NEED URGENT HELP!!! - A ship leaves port at 1:00 P.M. and sails in the ...
Calculus - Two ships leave the same port at noon. Ship A sails north at 22 mph, ...
math - at 12 noon ship A is 65 km due north of a second ship B. Ship A sails ...
Calculus - at 12 noon ship A is 65 km due north of a second ship B. Ship A sails...
calculus - Starting at point A, a ship sails 57 km on a bearing of 188°, ...
Navigation - A fisherman leaves his home port and heads in the direction N 70 ...
For Further Reading