Thursday

October 23, 2014

October 23, 2014

Posted by **Zac** on Wednesday, October 5, 2011 at 4:39pm.

ln(a + b) + ln(a - b) - 2 ln c

- Cal -
**PC**, Wednesday, October 5, 2011 at 4:46pmThe sum of two logarithms is equal to the logarithm of the product, and the difference equals the quotient:

log(A)+log(B)-log(C)

=log(AB/C)

Twice the logarithm of a quantity is the logarithm of the square of the quantity:

2log(C)=log(C²)

So if we put it all together, we get:

log(A)+log(B)-2log(C)

=log( AB/C²)

**Answer this Question**

**Related Questions**

Calculus - express the given quantity as a single logarithm: ln(a+b)+ln(a-b)-8ln...

calculus - Express the given quantity as a single logarithm. 1/3ln(x + 2)3 + 1/2...

Precalculus - 1. Write the given expression as a single logarithm. log(70x)+log(...

Calculus - Write as a single logarithm of a single quantity ln(3)+1/2ln(x+2)-...

algebra 3-4 - im in a cal class but were reviewing algebra stuff now. and i have...

Algebra II - Express as a single logarithm with a coefficient of 1. Assume that ...

Calculus - Write the expression as the logarithm of a single quantity. ln 2 + 1/...

Calculus - Write the logarithm of a single quantity: 2ln(x)+ln(4)-(1/2)ln(9)

math - okay, this i cannot figure out anywhere. 2[ln(x)-ln(x+1)-ln(x-1)] ...

math - write the expression as the logarithm of a single quantity. 2 In 8 + 5 In...