Posted by Zac on Wednesday, October 5, 2011 at 4:39pm.
The sum of two logarithms is equal to the logarithm of the product, and the difference equals the quotient:
log(A)+log(B)-log(C)
=log(AB/C)
Twice the logarithm of a quantity is the logarithm of the square of the quantity:
2log(C)=log(C²)
So if we put it all together, we get:
log(A)+log(B)-2log(C)
=log( AB/C²)
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