Posted by **Zac** on Wednesday, October 5, 2011 at 4:39pm.

Express the given quantity in a single logarithm.

ln(a + b) + ln(a - b) - 2 ln c

- Cal -
**PC**, Wednesday, October 5, 2011 at 4:46pm
The sum of two logarithms is equal to the logarithm of the product, and the difference equals the quotient:

log(A)+log(B)-log(C)

=log(AB/C)

Twice the logarithm of a quantity is the logarithm of the square of the quantity:

2log(C)=log(C²)

So if we put it all together, we get:

log(A)+log(B)-2log(C)

=log( AB/C²)

## Answer this Question

## Related Questions

- Calculus - express the given quantity as a single logarithm: ln(a+b)+ln(a-b)-8ln...
- calculus - Express the given quantity as a single logarithm. 1/3ln(x + 2)3 + 1/2...
- Precalculus - 1. Write the given expression as a single logarithm. log(70x)+log(...
- Calculus - Write as a single logarithm of a single quantity ln(3)+1/2ln(x+2)-...
- algebra 3-4 - im in a cal class but were reviewing algebra stuff now. and i have...
- Algebra II - Express as a single logarithm with a coefficient of 1. Assume that ...
- Calculus - Write the expression as the logarithm of a single quantity. ln 2 + 1/...
- Calculus - Write the logarithm of a single quantity: 2ln(x)+ln(4)-(1/2)ln(9)
- Math - Condense the expression to the logarithm of a single quantity. 5lnx-6ln(x...
- math - okay, this i cannot figure out anywhere. 2[ln(x)-ln(x+1)-ln(x-1)] ...

More Related Questions