150 mL of a 4.00 molar NaOH solution is diluted with water to a new volume of 1.00 liter. What is the new molarity of the NaOH?
Use mL1 x M1 = mL2 x M2 OR
look at it another way; i.e., you have diluted 4.00 molar from 150 to 1000 so
4.00 x (150/1000) = ??
You should obtain the same answer either way.
asdff
To find the new molarity of the NaOH solution after dilution, we need to use the equation:
\(M_1 \cdot V_1 = M_2 \cdot V_2\)
Where:
\(M_1\) is the initial molarity of the solution (4.00 M),
\(V_1\) is the initial volume of the solution (150 mL),
\(M_2\) is the final molarity of the solution (what we want to find), and
\(V_2\) is the final volume of the solution (1.00 L).
First, we need to convert the initial volume from milliliters (mL) to liters (L):
\(150 \, \text{mL} = 150 \times 10^{-3} \, \text{L} = 0.150 \, \text{L}\)
Now we can plug in the values into the equation:
\(4.00 \, \text{M} \cdot 0.150 \, \text{L} = M_2 \cdot 1.00 \, \text{L}\)
Solving for \(M_2\):
\(0.600 \, \text{M} = M_2\)
Therefore, the new molarity of the NaOH solution after dilution is 0.600 M.