Posted by LALAINE on Wednesday, October 5, 2011 at 7:28am.
A STONE IS DROPPED FROM A CLIFF SOME HIGH. DISREGARDING AIR RESISTENCE, (a) HOW LONG DOES IT TAKE THE STONE TO REACH THE GROUND? (b) WHAT IS ITS SPEED WHEN IT STRIKE THE AROUND?

physics  drwls, Wednesday, October 5, 2011 at 8:07am
You need to provide numbers like the cliff height. "Some high" won't cut it.
Please turn off your caps lock. It is like being yelled at.

physics  tchrwill, Wednesday, October 5, 2011 at 12:43pm
I assume you are looking for a general expression for the time it takes an object to fall from a cliff of height "h".
From h = Vot + gt^2/2
where H = the height of the cliff
Vo = the initial velocity = 0
g = acceleration due to gravity and t = the time of the fall.
Solving for t yields
t = sqrt(2h/g).
Choose your "h" and you have the time of the fall.

physics  nadia, Tuesday, January 17, 2012 at 8:56pm
h=100m t=200/9.8= 20.408 sec.
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