Posted by **LALAINE** on Wednesday, October 5, 2011 at 7:28am.

A STONE IS DROPPED FROM A CLIFF SOME HIGH. DISREGARDING AIR RESISTENCE, (a) HOW LONG DOES IT TAKE THE STONE TO REACH THE GROUND? (b) WHAT IS ITS SPEED WHEN IT STRIKE THE AROUND?

- physics -
**drwls**, Wednesday, October 5, 2011 at 8:07am
You need to provide numbers like the cliff height. "Some high" won't cut it.

Please turn off your caps lock. It is like being yelled at.

- physics -
**tchrwill**, Wednesday, October 5, 2011 at 12:43pm
I assume you are looking for a general expression for the time it takes an object to fall from a cliff of height "h".

From h = Vot + gt^2/2

where H = the height of the cliff

Vo = the initial velocity = 0

g = acceleration due to gravity and t = the time of the fall.

Solving for t yields

t = sqrt(2h/g).

Choose your "h" and you have the time of the fall.

- physics -
**nadia**, Tuesday, January 17, 2012 at 8:56pm
h=100m t=200/9.8= 20.408 sec.

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