Find the standard entropy (S^0) of ice at 25K. delta Hfus = 6009 J/mol and Cp of ice = 38 J/molK.
To find the standard entropy (S^0) of ice at 25 K, we can use the equation:
ΔS^0 = ΔHfus / T
Where:
ΔS^0 is the standard entropy change,
ΔHfus is the enthalpy of fusion, and
T is the temperature in Kelvin.
Given that ΔHfus is 6009 J/mol and the temperature is 25 K, we can substitute these values into the equation to find ΔS^0:
ΔS^0 = 6009 J/mol / 25 K
To simplify the units, we need to convert the enthalpy change from joules (J) to kilojoules (kJ). Since 1 kJ = 1000 J, we have:
ΔS^0 = 6009 J/mol / (25 K * 1000 J/ 1 kJ)
ΔS^0 = 2.404 kJ/mol / 25 K
ΔS^0 = 0.09616 kJ/molK
Therefore, the standard entropy (S^0) of ice at 25 K is approximately 0.09616 kJ/molK.