Posted by Jack on Tuesday, October 4, 2011 at 9:49pm.
f(x) = x - 1/(1+5x)
= x - (1+5x)^-1
f'(x) = 1 + (1+5x)^-2 (5)
= 1 + 5/(1+5x)^2
the slope of x-2y=2 is 1/2
so
1 + 5/(1+5x)^2 = 1/2
5/(1+5x)^2 = -1/2
(1+5x)^2 = -10
A square of something cannot be negative, so
either there is no solution or you made an error in typing.
Was the equation perhaps
f(x) = (x-1)/(1+5x) ?
yeah that's what I meant
Related Questions
Calculus - If f(x)=[(x−1)/(1+5x)], there are two points on the graph ...
Calculus - Find all points at which the graph of f (x) = x^3 −3x has ...
Calculus - a)The curve with equation: 2y^3 + y^2 - y^5 = x^4 - 2x^3 + x^2 has ...
Calculus - Consider the curve y^2+xy+x^2=15. What is dy/dx? Find the two points ...
Calculus (Urgent Help) - The graph of y=cos x * ln cos^2x has seven horizontal ...
Calculus (Urgent Help) - The graph of y=cos x * ln cos^2x has seven horizontal ...
Calculus (Help) - The graph of y=cos x * ln cos^2x has seven horizontal tangent ...
Calculus (Help) - The graph of y=cos x * ln cos^2x has seven horizontal tangent ...
Calculus - Let f(x)=21−x^2 The slope of the tangent line to the graph ...
Calculus - Given the function y=(x^2-5/x+3), answer the following questions. a) ...
For Further Reading