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April 16, 2014

April 16, 2014

Posted by **Jack** on Tuesday, October 4, 2011 at 9:49pm.

y=f(x) at which the tangent lines are parallel to the line x−2y=2.

Type in the x values of

these points. Type the smaller number first, then the larger number.

- Calculus -
**Reiny**, Tuesday, October 4, 2011 at 10:23pmf(x) = x - 1/(1+5x)

= x - (1+5x)^-1

f'(x) = 1 + (1+5x)^-2 (5)

= 1 + 5/(1+5x)^2

the slope of x-2y=2 is 1/2

so

1 + 5/(1+5x)^2 = 1/2

5/(1+5x)^2 = -1/2

(1+5x)^2 = -10

A square of something cannot be negative, so

either there is no solution or you made an error in typing.

Was the equation perhaps

f(x) = (x-1)/(1+5x) ?

- Calculus -
**Jack**, Tuesday, October 4, 2011 at 10:27pmyeah that's what I meant

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