Physics
posted by Kels on .
A spring has a spring constant of 42 N/m. How much work is required to stretch the spring 1.5 cm from its equilibrium position?

work= 1/2 k x^2 = 1/2 42N/m * (.0015m)^2
posted by Kels on .
A spring has a spring constant of 42 N/m. How much work is required to stretch the spring 1.5 cm from its equilibrium position?
work= 1/2 k x^2 = 1/2 42N/m * (.0015m)^2