Tuesday

September 23, 2014

September 23, 2014

Posted by **George** on Tuesday, October 4, 2011 at 5:21pm.

I am getting t = 22.06, and its wrong :( Could someone help me out please!

-Thanks

- Physics -
**drwls**, Tuesday, October 4, 2011 at 8:21pmYou need to provide dimensions with your numbers. That could be why you got the wrong answer.

- Physics -
**Kitty Perez**, Thursday, October 6, 2011 at 12:47amSince Xf for the police is going to be equal to the Xf of the speeder we know that we can write two equations for the speeder and the police and set them equal to each other in order to solve for t.

first we need to convert

Police: v1=80km/hr-->22.22m/s

Speeder: v2=145km/hr-->40.27 m/s

Police: Xf= vt + (0.5)(a)t^2

Xf=22.22*t+(0.5)(1.8)(t-2.5)^2

Speeder:

Xf=40.27*t

Solve for t by setting the eqns equal to each other

So we get:

0.9t^2-22.55t+5.63

use the quad. eqn to solve for t

t=24.8

**Answer this Question**

**Related Questions**

Physics. - An unmarked police car traveling a constant 95 km/h is passed by a ...

Physics - An unmarked police car traveling a constant 80km/h is passed by a ...

physics - An unmarked police car traveling a constant 95km/h is passed by a ...

Physics - An unmarked police car traveling a constant 80 km/h is passed by a ...

physics - college - An unmarked police car traveling a constant 95km/h is ...

physics - college - An unmarked police car traveling a constant 95km/h is ...

college physics 44 - An unmarked police car traveling a constant 95km/h is ...

physics - An unmarked police car traveling a constant 90 km/h is passed by a ...

physic - An unmarked police car traveling a constant 95km/h is passed by a ...

physics - A speeding motorist traveling 125 km/h passes a stationary police ...