Thursday

July 31, 2014

July 31, 2014

Posted by **Anonymous** on Tuesday, October 4, 2011 at 5:14pm.

- calculus -
**Steve**, Tuesday, October 4, 2011 at 8:13pmLet the woman be b feet from the pole, and let her shadow be a feet long.

Using similar triangles,

a/6 = (a+b)/16

so a = 3/5 b

da/dt = 3/5 db/dt = 3/5 * 4 = 12/5 ft/sec, a constant speed.

That seems odd. I expected her shadow's length to accelerate, but I don't see an error. These problems usually involve a steadily changing angle, and with the tangent function things speed up quickly. Not so here...

**Related Questions**

Calculus - A street light is at the top of a 17 ft tall pole. A woman 6 ft tall ...

Calculus - A street light is at the top of a 17 ft tall pole. A woman 6 ft tall ...

calculus - A street light is at the top of a 13 ft tall pole. A woman 6 ft tall ...

calculus - A street light is at the top of a 20 ft tall pole. A woman 6 ft tall ...

calculus - A street light is at the top of a 15 ft tall pole. A woman 6 ft tall ...

calculus - A street light is at the top of a 16 ft tall pole. A woman 6 ft tall...

Calculus 1 - A street light is at the top of a 19 ft tall pole. A woman 6 ft ...

calculus - A street light is at the top of a 17 ft tall pole. A woman 6 ft tall ...

calculus - A street light is at the top of a 19 ft tall pole. A woman 6 ft tall ...

Calculus - A street light is at the top of a 19 foot tall pole. A 6 foot tall ...