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November 25, 2014

November 25, 2014

Posted by **Anonymous** on Tuesday, October 4, 2011 at 5:14pm.

- calculus -
**Steve**, Tuesday, October 4, 2011 at 8:13pmLet the woman be b feet from the pole, and let her shadow be a feet long.

Using similar triangles,

a/6 = (a+b)/16

so a = 3/5 b

da/dt = 3/5 db/dt = 3/5 * 4 = 12/5 ft/sec, a constant speed.

That seems odd. I expected her shadow's length to accelerate, but I don't see an error. These problems usually involve a steadily changing angle, and with the tangent function things speed up quickly. Not so here...

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