posted by Robyn on .
For the acid-base neutralization reaction of Carbonic acid, H2CO3(aq) and lithium hydroxide, LiOH(aq), write the blanced:
b) Ionic equation
c) Net ionic equation.
a) H2CO3(aq) + 2LiOH(aq) = 2H2O(l) +Li2CO3(aq)
i know my answers for the next are not right i'm just confused how to start these equations.Please help! :)
To write net ionic equations you follow some rules. Some things that are written as molecules are
1. weak electrolytes (those that do not ionize 100% such as weak acids(those with a Ka), weak bases (those with a Kb), H2O, ETC.
b. insoluble materials (memorize the solubility rules). Here is a simplified set of rules. http://www.files.chem.vt.edu/RVGS/ACT/notes/solubility_rules.html
Everything else is written as ions.
H2CO3(aq) + 2Li^+(aq) + 2OH^-(aq) ==>2H2O(l) + 2Li^+(aq) + CO3^2-(aq)
What I have written above is the ionic equation. To write the net ionic equation, we cancel any ions common to both sides. Therefore, we cancel 2Li^+(aq) and rewrite the net ionic equation as
H2CO3(aq) + 2OH^-(aq) ==>2H2O(l) + CO3^2-(aq)