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December 19, 2014

December 19, 2014

Posted by **anil** on Tuesday, October 4, 2011 at 9:03am.

(3x2 – 5ax + a2)4

- MBA – I/ Semester – I math -
**Reiny**, Tuesday, October 4, 2011 at 10:03amI will assume that you have exponents, and it is ...

y = (3x^2 - 5ax + a^2)^4 , where a is a constant

dy/dx = 4(3x^2 - 5ax + a^2)^3 (6x - 5a)

= 4(6x-5a)(3x^2 - 5ax + a^2)^3

let me know if a is NOT a constant.

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