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November 27, 2014

November 27, 2014

Posted by **Nilan** on Tuesday, October 4, 2011 at 7:18am.

I understand I could start with (x+3)(x-5)^2, but i don't know how to get the y-intercept 1350 with the same conditions. Please help. thank you.

- Algebra -
**Reiny**, Tuesday, October 4, 2011 at 8:22amyou are only given two roots, so let the equation be

y = (x+3)(x-5)(x-a)

but you know that (0,1350) lies on it

1350 = (3)(-5)(-a)

1350 = 15a

a = 90

so equation is

y = (x+3)(x-5)(x-90)

expand if you have to, it is more useful in factored form.

btw, your equation of y = ....(x-5)^2 would have a double root of 5, that is, it would "touch" the x-axis at x = 5

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