Posted by Peter on Tuesday, October 4, 2011 at 12:36am.
C = 12000 p + 10000 q
40 p + 80 q >/= 2000
40 p + 30 q >/= 1500
12 p + 40 q >/= 2400
or
p + 2 q >/= 50
4 p + 3 q >/= 150
3 p + 10 q >/= 60
Graph those lines
You will see that the First two lines are way up there to the right and above the third. Therefore only the first two need be investigated
They intersect at:
4 p + 8 q = 200
4 p + 3 q = 150
-----------------
5 q = 50
q = 10
p = 30 so (p,q) at (30,10)
also axis intersections at (0,50) and (50,0)
test those three for cost
12p + 10 q or 6 p + 5 q
at intersection (30,10)
6*30+5*10 =230
at (0,50)
6*0 + 5*50 = 250
at (50,0)
6*50 + 0 = 300
so min cost at (30,10)
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