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February 28, 2015

February 28, 2015

Posted by **Peter** on Tuesday, October 4, 2011 at 12:36am.

- Algebra 2 (Linear Programming) -
**Damon**, Tuesday, October 4, 2011 at 1:34amC = 12000 p + 10000 q

40 p + 80 q >/= 2000

40 p + 30 q >/= 1500

12 p + 40 q >/= 2400

or

p + 2 q >/= 50

4 p + 3 q >/= 150

3 p + 10 q >/= 60

Graph those lines

You will see that the First two lines are way up there to the right and above the third. Therefore only the first two need be investigated

They intersect at:

4 p + 8 q = 200

4 p + 3 q = 150

-----------------

5 q = 50

q = 10

p = 30 so (p,q) at (30,10)

also axis intersections at (0,50) and (50,0)

test those three for cost

12p + 10 q or 6 p + 5 q

at intersection (30,10)

6*30+5*10 =230

at (0,50)

6*0 + 5*50 = 250

at (50,0)

6*50 + 0 = 300

so min cost at (30,10)

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