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December 22, 2014

December 22, 2014

Posted by **Amie** on Tuesday, October 4, 2011 at 12:27am.

f(x) = −x2 + 10x

- Pre-Calculus -
**drwls**, Tuesday, October 4, 2011 at 6:43amAll you have done is define f(x).

There is no "solution"

If you had written

f(x) = (any constant),

there would be a solution.

- Pre-Calculus -
**Steve**, Tuesday, October 4, 2011 at 11:24amNow, if you want to solve f(x) = 0,

f(x) = -2x(x-5)

so, f=0 when either factor is zero. This is why we always set f(x) = 0 to solve for x, because the only time a product of numbers is zero is when one of them is zero. If we had -2x(x-5) = 12, well, that doesn't help us because there are lots of numbers that multiply to equal 12. But if the product is zero, then one of the factors must be zero.

so, x=0 or x=5 will make f(x) = 0

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