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November 29, 2014

November 29, 2014

Posted by **Chris** on Monday, October 3, 2011 at 11:48pm.

- math -
**Steve**, Tuesday, October 4, 2011 at 11:12amGiven angle c, ACB

construct a circle with center C intersecting AC at D and CB at E.

Using D as a center, construct a circle with radius DE so it intersects the circle C at F.

Angle FCA = ACB since they subtend equal arcs.

So, FCB = FCA+ACB = 2*ACB

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