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August 29, 2014

August 29, 2014

Posted by **kay** on Monday, October 3, 2011 at 11:30pm.

- geometry -
**tchrwill**, Tuesday, October 4, 2011 at 10:50am1--Let A and B = the two height of the two poles.

2--Let X = the height of the poles crossing.

3--Let C be the distance between the two poles.

4--From the figure, A/C = X/Y or AY = CX.

5--Similarly, B/C = X/(C - Y) or BY = BC - CX.

6--Y = CX/A = (BC - CX)/B from which X = AB/(A+B).

Note - X is actually one half the harmonic mean of the two dimensions A and B, the harmonic mean being 2AB/(A + B).

Therefore, the height of the crossing is totally independant of the distance between the two buildings.

- geometry -
**Steve**, Tuesday, October 4, 2011 at 10:53amThe height h is given by 1/h = 1/60 + 1/20

h = 15'

This is true regardless of the width of the field.

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