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Physics

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if the speed of the block is 9.5 m/s at the bottom of the ramp, from what height was the block released? what is the length of the ramp?" and i know that the mass is 7 kg, initial veloctity=0, it is frictionless, and inclined at an angle of 62 degreesif the speed of the black is 9.5 m/s at the bottom of the ramp, from what height was the block released? what is the length of the ramp?" and i know that the mass is 7 kg, initial veloctity=0, it is frictionless, and inclined at an angle of 62 degrees

  • Physics - ,

    the vertical acceleration is 9.8 * sin 62° = 8.652

    s = 1/2 at² = 4.326 t²
    v = at = 8.652t = 9.5, so
    t = 1.098s

    s = 4.326 * 1.098² = 5.22m

    that's the height. The ramp length would be longer

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