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September 30, 2014

September 30, 2014

Posted by **Nilan** on Monday, October 3, 2011 at 10:01pm.

I understand I could start with (x+3)(x-5)^2, but i don't know how to get the y-intercept 1350 with the same conditions. Please help. thank you.

- Math -
**Steve**, Tuesday, October 4, 2011 at 9:00amWe don't know that 5 is a double root. So,

y = (x+3)(x-5)(x-k) = <powers of x> + 15k

So, since the y-intercept is where x=0, all the <powers of x> go away and we have 15k = 1350

k = 90

y = (x+3)(x-5)(x-90)

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