Posted by Wendell on Monday, October 3, 2011 at 9:37pm.
HNO3 + NaOH ==> NaNO3 + HOH
Notice ratio acid/base = 1:1
pH 3.78 = (H^+) = (HNO3) = 1.7E-4 (approximate--you should do it more accurately.)
1.7E-4 moles/L x 1.6E4L = about 3 moles = moles HNO3 = moles NaOH needed.
M NaOH = moles NaOH/L NaOH. You have M and moles, solve for L.
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