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April 17, 2014

April 17, 2014

Posted by **Wendell** on Monday, October 3, 2011 at 9:37pm.

- Chemistry II -
**DrBob222**, Monday, October 3, 2011 at 10:32pmHNO3 + NaOH ==> NaNO3 + HOH

Notice ratio acid/base = 1:1

pH 3.78 = (H^+) = (HNO3) = 1.7E-4 (approximate--you should do it more accurately.)

1.7E-4 moles/L x 1.6E4L = about 3 moles = moles HNO3 = moles NaOH needed.

M NaOH = moles NaOH/L NaOH. You have M and moles, solve for L.

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