Three identical masses of 640 each are placed on the x axis. One mass is at = -100 , one is at the origin, and one is at = 400 .

What is the magnitude of the net gravitational force on the mass at the origin due to the other two masses?
Take the gravitational constant to be = 6.67×10−11 .

No dimensions for your numbers.

Therefore no help.

To find the magnitude of the net gravitational force on the mass at the origin, we need to calculate the individual gravitational forces between the origin mass and the other two masses, and then sum them up.

The formula for the gravitational force between two objects is given by:

F = (G * m1 * m2) / r^2

Where F is the gravitational force, G is the gravitational constant, m1 and m2 are the masses of the objects, and r is the distance between the centers of the two objects.

Let's calculate the gravitational forces between the origin mass and the other two masses:

1. Gravitational force between the origin mass and the mass at = -100:

F1 = (G * m * m) / r^2

Here, m represents the mass, G is the gravitational constant, and r is the distance between the masses.

Given:
m = 640 kg
r = (-100) - 0 = 100

Plugging in these values, we can calculate F1:

F1 = (6.67×10^-11 * 640 * 640) / 100^2

2. Gravitational force between the origin mass and the mass at = 400:

F2 = (G * m * m) / r^2

Given:
m = 640 kg
r = 400 - 0 = 400

Plugging in these values, we can calculate F2:

F2 = (6.67×10^-11 * 640 * 640) / 400^2

Now, let's calculate the net gravitational force by summing up the individual forces:

Net force = F1 + F2

Substituting the values of F1 and F2, we can calculate the net gravitational force.