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December 21, 2014

December 21, 2014

Posted by **tatiana** on Monday, October 3, 2011 at 8:26pm.

- pre-calculus -
**Reiny**, Monday, October 3, 2011 at 9:04pmI am sure you meant to say

sinx/(sinx+cosx) = tanx/(1+tanx)

RS = (sinx/cosx)/[1 + sinx/cosx]

= (sinx/cosx)/[(cosx+sinx)/cosx]

= (sinx/cosx) ( cosx/(cosx + sinx))

= sinx/(cosx + sinx)

= LS

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