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pre-calculus

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How do I prove that sinx/sinx+cosx=tanx/1+tanx

  • pre-calculus - ,

    I am sure you meant to say
    sinx/(sinx+cosx) = tanx/(1+tanx)

    RS = (sinx/cosx)/[1 + sinx/cosx]
    = (sinx/cosx)/[(cosx+sinx)/cosx]
    = (sinx/cosx) ( cosx/(cosx + sinx))
    = sinx/(cosx + sinx)
    = LS

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